If `alpha,beta,gamma` are the roots of `x^3+3x+3=0` then `alpha^5+beta^5+gamma^5=`

If alpha, beta, gamma are the roots of x^(3) - 3x + 7 = 0 then alpha beta gamma =

If alpha, beta, gamma are the roots of x^(3) - 3x + 7 = 0 then alpha + beta + gamma =

If alpha, beta, gamma are the roots of x^(3)+px+q=0 then |(alpha, beta, gamma),(beta, gamma, alpha),(gamma, alpha, beta)|=

If alpha , beta, gamma are the roots of x^3+x^2-5x-1=0 then alpha+beta+gamma is equal to

If alpha , beta , gamma are the roots of x^3 + 2x^2 + 3x +8=0 then ( alpha + beta ) ( beta + gamma) ( gamma + alpha ) =

If alpha , beta , gamma are the roots of x^3 + 2x^2 + 3x +8=0 then ( alpha + beta ) ( beta + gamma) ( gamma + alpha ) =

If alpha,beta,gamma are the zeroes of 3x^3-5x^2-11x-3 , then alpha+beta+gamma =

If alpha,beta, gamma are the roots of 4x^(3) - 6x^(2) + 7x + 3 = 0 then alpha beta + alpha beta + alpha gamma =

If alpha,beta,gamma are the roots of x^(3)+2x^(2)+3x+8=0 then (alpha+beta)(beta+gamma)(gamma+alpha)=