`x^(2)-2ax-(4b^(2)-a^(2))=0`

36x^(2)-12ax+(a^(2)-b^(2))=0

Solve the following quadratic equation for x.x^(2)-4ax-b^(2)+4a^(2)=0

Solve 4x^(2)-4ax+(a^(2)-b^(2))=0.

Solve the following quadratic equation by factorization method: ( ) x^(2)-2ax+a^(2)-b^(2)=0(ii)x^(2)-4ax+4a^(2)-b^(2)=0(iii)4x^(2)-4ax+(a^(2)-b^(2))=0(iv)4x^(2)-4a^(2)x+(a^(4)-b^(4))=

Find the roots (if they exist) by completing the square: x^(2)-4ax+4a^(2)-b^(2)=0

Solve each of the following equatins : 4x^(2)-4ax+(a^(2)+b^(2))=0

Solve each of the following equatins : 4x^(2)-4ax+(a^(2)+b^(2))=0

Find the roots of x^(2)-4ax+4a^(2)-b^(2)=0 if they exist by method of completing the square.

If a circle passes through the point (a, b) and cuts the circle x^2 + y^2 = 4 orthogonally, then the locus of its centre is (a) 2ax+2by-(a^(2)+b^(2)+4)=0 (b) 2ax+2by-(a^(2)-b^(2)+k^(2))=0 (c) x^(2)+y^(2)-3ax-4by+(a^(2)+b^(2)-k^(2))=0 (d) x^(2)+y^(2)-2ax-3by+(a^(2)-b^(2)-k^(2))=0

The roots of the equation x^(2)+2ax+a^(2)+b^(2)=0 are