If n is any natural number, then 6^n-...

If `n` is any natural number, then `6^n-5^n` always ends with (a) 1 (b) 3 (c) 5 (d) 7 [Hint: For any `n in N ,\ 6^n\ ` and `5^n` end with 6 and 5 respectively. Therefore, `6^n-5^n` always ends with `6-5=1.]`

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