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Let S e the sum, P the product, adn R th...

Let `S` e the sum, `P` the product, adn `R` the sum of reciprocals of `n` terms in a G.P. Prove that `P^2R^n=S^ndot`

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To prove that \( P^2 R^n = S^n \) for the sum \( S \), product \( P \), and sum of reciprocals \( R \) of \( n \) terms in a geometric progression (G.P.), we will follow these steps: ### Step 1: Define the terms of the G.P. Let the first term of the G.P. be \( a \) and the common ratio be \( r \). The \( n \) terms of the G.P. can be expressed as: \[ a, ar, ar^2, ar^3, \ldots, ar^{n-1} \] ...
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