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An object is observed from three points ...

An object is observed from three points `A, B,C` in the same horizontal line passing through the base of the object. The angle of elevation at `B` is twice and at `C` is thrice than that at `A`. If `AB=a, BC=b` prove that the height of the object is `h=(a/(2b))sqrt((a+b)(3b-a))`

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