A particle is moving with speed `6m//s` along the direction of `vec(A)=2hat(i)+2hat(j)-hat(k)`, then its velocity is `:`

A particle is moving with speed 6 m//s along the direction of vec(A) =2 hat i+2 hat j- hat k , then its velocity is :

A particle is moving with speed 6m/s along the direction of 2hat(i)+2hat(j)-hat(k) find the velocity vector of a particle ?

Direction - cosines of vec(a)=hat(i)+hat(j)-2hat(k) are :

A particle is moving with a constant acceleration vec(a) = hat(i) - 2 hat(j) m//s^(2) and instantaneous velocity vec(v) = hat(i) + 2 hat(j) + 2 hat(k) m//s then rate of change of speed of particle 1 second after this instant will be :

A particle is moving with a constant acceleration vec(a) = hat(i) - 2 hat(j) m//s^(2) and instantaneous velocity vec(v) = hat(i) + 2 hat(j) + 2 hat(k) m//s then rate of change of speed of particle 1 second after this instant will be :

A particle moves in the x-y plane under acceleration vec(a) = 3hat(i) + 4hat(j) m//s^(2) . If the initial velocities is vec(u) = 6hat(i) + 8hat(j) m//s . Find the velocity and the position vector of a particle after 2 s .

A particle moves 21m along the vector 6hat(i)+2hat(j)+3hat(k) , then 14 m along the vector 3hat(i)-2hat(j)+6hat(k) . Its total displacement (in meters) is

A particle moves 21m along the vector 6hat(i)+2hat(j)+3hat(k) , then 14 m along the vector 3hat(i)-2hat(j)+6hat(k) . Its total displacement (in meters) is

A particle moves 21m along the vector 6hat(i)+2hat(j)+3hat(k) , then 14 m along the vector 3hat(i)-2hat(j)+6hat(k) . Its total displacement (in meters) is

What is the projection of vec(a)=(2hat(i)-hat(j)+hat(k)) on vec(b)=(hat(i)-2hat(j)+hat(k))?