" d) "(x^(2)-4x)(x^(2)-4x-1)-20

Factorize :(x^(2)-4x)(x^(2)-4x-1)-20

Factorize : (x^2-4x)(x^2-4x-1)-20

Factorize : (x^2-4x)(x^2-4x-1)-20

Factorize the following expressions (x^2-4x)(x^2-4x-1)-20

(d)/(dx)[log{e^(x)((x-2)/(x+2))^(3/4)}] equals (x^(2)-1)/(x^(2)-4) (b) 1 (c) (x^(2)+1)/(x^(2)-4) (d) e^(x)(x^(2)-1)/(x^(2)-4)

The biquadratic equation, two of whose roots are 1+i , 1-sqrt(2) is A) x^(4)-4x^(3)+5x^(2)-2x-2=0 B) x^(4)-4x^(3)-5x^(2)+2x+2=0 C) x^(4)+4x^(3)-5x^(2)+2x-2=0 D) x^(4)+4x^(3)+5x^(2)-2x+2=0

If f(x) = {((x^(2)-4x+3)/(x^(2)-1), ",","for"x != 1),(2, ",", "for"x = 1 ):} , then

If f(x) {:(=(x^(2)-4x+3)/(x^(2)-1)", ..."x!=1 ),( =2", ..."x=1):} then :

If y=(1+(1)/(x^(2)))/(1-(1)/(x^(2)))backslash then (dy)/(dx)=-(4x)/((x^(2)-1)^(2))b-(4x)/(x^(2)-1) c.(1-x^(2))/(4x)d*(4x)/(x^(2)-1)