[3x+y+1=0],[2x-3y+8=0]

2(2x+y+5)+3(x-3y-1)=0 2x-3y+1=0

Solve the following system of equations graphically: 3x+y+1=0;quad 2x-3y+8=0

Solve [2x+3y-7=0],[3x+2y-8=0]

Solve: {:(3x - 4y - 1 = 0),(2x - (8)/(3)y + 5 = 0):}

The line common to the given families of line a(x +y+1)+b(2x-3y-8)=0 and lambda(x-y-1)+mu (2x-y-1)=0 is : x+y+1=0 x+y-1=0 x+y-1=0 None of these

Write the ascending order of the distance between the parallel lines (A) 2x+3y+1=0, 2x+3y+14=0 (B) 3x+4y+10=0, 3x+4y+5=0 (C) x+y+1=0, x+y+3=0 (D) 2x+y+1=0, 2x+y+6=0

Prove that the lies 3x+y-14=0,\ x-2y=0\ n a d\ 3x-8y+4=0 are concurrent.

Prove that the lies 3x+y-14=0,x-2y=0 nad 3x-8y+4=0 are concurrent.

Solve for x and y - 2x+3y-8=0 3x+4y-5=0