An electronic assembly consists of two subsystems, say, A and B. From previous testing procedures, the following probabilities are assumed to be known:P(A fails) = 0.2P(B fails alone) = 0.15P(A and B fail) = 0.15Evaluate the following probabilities(i) P(A fails B has failed)         (ii) P(A fails alone)

Explanation

Let the event in which A fails and B fails be denoted by A​ and B​
.

P(A​)=0.2


P(A​∩E​)=0.15

P(B fails alone)=`P(B​)−P(A​∩B)`


=`0.15=P(B​)−0.15`

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