y=-|x+2|

The factors of x^3-x^2y-x y^2+y^3 are (a (x+y)(x^2-x y+y^2) (b) (x+y)(x^2+x y+y^2) (c) (x+y)^2(x-y) (d) (x-y)^2(x+y)

y=2-x^(2), y=x^(2)

The area of the region bounded by y=x^(2) and y=-x^(2)+2 is

Which of the following pair of graphs intersect? y=x^2-x a and y=1 y=x^2-2x and y=sinx y=x^2-x+1 and y=x-4

Let's simplify:- (x + y) (x^2 -xy + y^2) + ( x - y) (x^2 + xy + y^2)

Suppose y=x^(2) . Describe the graph of y=(x+2)^(2) .

Add the algebraic expressions: 4x y^2-7x^2y ,\ 12 x^2y-6x y^2,\ -3x^2y+5x y^2

The axis of a parabola is along the line y=x and the distance of its vertex and focus from the origin are sqrt(2) and 2sqrt(2), respectively.If vertex and focus both lie in the first quadrant, then the equation of the parabola is (x+y)^(2)=(x-y-2)(x-y)^(2)=4(x+y-2)(x-y)^(2)=4(x+y-2)(x-y)^(2)=4(x+y-2)(x-y)^(2)=8(x+y-2)

(x-y^2x)dx=(y-x^2y)dy