[" Question "27],[" In a YDSE for wavelength "lambda=589nm," The interference "],[" fringes have angular separation of "3.5times10^(-3)" radians for what "],[" wavelength the angular separation be "10%" greater? "]

In YDSE for wavelength lambda = 589nm , the interference fringe have angular separation of 3050 xx 10^(-3) rad. For what wavelength would the angular separation be 10.0% greater?

In YDSE for wavelength lambda = 589nm , the interference fringe have angular separation of 3050 xx 10^(-3) rad. For what wavelength would the angular separation be 10.0% greater?

A double slit arrangement produces interference fringes for sodium light (lambda=589nm) that have an angular separation of 3.50xx10^-3 radian. For what wavelength would the angular separation be 10% greater?

A double-slit arrangement produces interference fringes for sodium light ( lambda= 589 nm ) that have an angular separation of 3.50 xx 10^(-3) rad. For what wavelength would the angular separation be 6.0% greater?

A double-slit experiment, arrangement produces interference fringes for sodium light (lambda = 589 nm) that have an angular separation of 3.50 xx 0^(-3) rad . For what wavelength would the angular separation to 10% greater?

A double-slit experiment, arrangement produces interference fringes for sodium light (lambda = 589 nm) that have an angular separation of 3.50 xx 0^(-3) rad . For what wavelength would the angular separation to 10% greater?

The interference fringes for sodium light (lambda = 5890 Å) in a double slit experiment have an angular width of 0.2^(@) . For what wavelength will width be 10% greater.

In YDSE performed with wavelength lambda = 5890 Å the angular fringe width is 0.40^(@) . What is the angular fringe width if the entire set-up is immersed in water?

In YDSE performed with wavelength lambda = 5890 Å the angular fringe width is 0.40^(@) . What is the angular fringe width if the entire set-up is immersed in water?

In a Y.D.S.E, light of wavelength 500 nm is used. The separation between bright fringes is 7.5 mm., calculate the fringe width if light is replaced by another light of wavelength 650 nm and separation between the slits is increased to 1.5 times.