" (vii) "(y-(x)/(10))(y+(x)/(10))

(x/10+y)(x/10-y)=?

If 2cos alpha = x + (1) / (x), 2cos beta = y + (1) / (y) then (x ^ (10)) / (y ^ (12)) - (y ^ (12)) / ( x ^ (10)) =

if sqrt((x)/(y))+sqrt((y)/(x))=(10)/(3) and x+y=10, then the value of xy will be :

Find the square root of the expressions (x^(2))/(y^(2))-10(x)/(y)+27-10(y)/(x)+(y^(2))/(x^(2))

Find the inverse of the function : y=(10^(x)-10^(-x))/(10^(x)+10^(-x))+1

x^(log_(10)((y)/(z))).y^(log_(10)((z)/(x))).z^(log_(10)((x)/(y))) is equal to :

x^(log_(10)((y)/(z))).y^(log_(10)((z)/(x))).z^(log_(10)((x)/(y))) is equal to :