Find the sum to `n` terms of the series `3//(1^2xx2^2)+5//(2^2xx3^2)+7//(3^2xx4^2)+dot`

The sum of 10 terms of the series (3)/(1^(2)xx2^(2))+(5)/(2^(2)xx3^(2))+(7)/(3^(2)xx4^(2))+… is

Find the sum to n terms of the series: (3)/(1^(2).2^(2))+(5)/(2^(2).3^(2))+(7)/(3^(2).4^(2))+

Find the sum of first n terms of the series 3/(1^(2).2^(2))+5/(2^(2).3^(2))+7/(3^(2).4^(2))+.......+ and deduce the sum of infinity .

Find the sum to n terms of the series: (1)/(1xx2)+(1)/(2xx3)+(1)/(3xx4)+

Find the sum to n terms of the series 1/(1xx2)+1/(2xx3)+1/(3xx4)+...+1/n(n+1)

Find the sum to n terms of the series: 1xx2xx3+2xx3xx4+3xx4xx5+.

Find the sum to n terms of the series 1xx2+2xx3+3xx4+4xx5+......

Let S_(n) denote the sum of n terms of the series 1^(2)+3xx2^(2)+3^(2)+3xx4^(2)+5^(2)+3xx6^(2)+7^(2)+ . . . . Statement -1: If n is odd, then S_(n)=(n(n+1)(4n-1))/(6) Statement -2: If n is even, then S_(n)=(n(n+1)(4n+5))/(6)