A certain ideal solution of two liquids `A` and `B` has mole fraction of `0.3` and `0.5` for the vapour phase and liquid phase, respectively. What would be the mole fraction of `B` in the vapour phase, when the mole fraction of `A` in the liquid is `0.25`?

If Pa and Pb are 108 and 36 torr respectively. What will be the mole fraction of A is vapour phase if B has mole fraction in solution 0.5:

Two liquids A and B form an ideal solution. The ratio of vapour pressures of pure liquids A and B are 3: 5. If the mole fraction of A in the liquid solution at equilibrium with vapours is 0.4, then the mole-fraction of B in the liquid is

At constant temperature , in a closed vessel, an ideal solution is formed by liquid-A and liquid -B and mole fraction of A and B are0.6 and 0.4 respectively. If vapour pressure of pure liquids are 125.0 and 62.5 mm respectively, then their mole fraction in vapour state are respectively ( In vessel, no other component is in gaseous form. )

Two liquids A and B have P_(A)^(@) and P_(B)^(@) in the ratio of 1:3 and the ratio of number of moles of A and B in liquid phase are 1:3 then mole fraction of A in vapour phase in equilibrium with the solution is equal to :

Two liquids A and B have P_A^(@)" and P_B^(@) in the ratio of 1 : 3 and the ratio of number of moles of A and B in liquid phese are 1 : 3 then mole fraction of 'A' in vapour phase in equilibrium with the solution is equal to :

Two liquids A and B have P_A^(@)" and P_B^(@) in the ratio of 1 : 3 and the ratio of number of moles of A and B in liquid phese are 1 : 3 then mole fraction of 'A' in vapour phase in equilibrium with the solution is equal to :

Two liquids A and B have P_A^(@)" and P_B^(@) in the ratio of 1 : 3 and the ratio of number of moles of A and B in liquid phese are 1 : 3 then mole fraction of 'A' in vapour phase in equilibrium with the solution is equal to :

Consider two cylinder piston assembly as shown in figure (a) and in figure (b) are kept in vacuum. Assume both piston are massless. Let two masses m_(1) and m_(2) are kept on the piston as shown in figure. Values of m_(1) and m_(2) are in the range in which both liquid and vapour phase coexist and are in equilibrium. Solution I contains 10 moles of liquid A and 10 moles of liquid B while solution II contains 8 moles of liquid A and 12 moles of liquid B. Let liquids A and B are completely miscible and form an ideal binary solution. Given : P_(A)^(@) = 100 torr, P_(B)^(@) = 60 torr, Let X_(A) = mole fraction of A in liquid phase in solution I X'_(A) = mole fraction of A in liquid phase in solution II Y_(A) = mole fraction of A in vapour phase in solution I Y'_(A) = mole fraction of A in vapour phase in solution II Mole fraction of A in liquid phase when 10 moles of solution is vapoursied in solution II is :

The liquids X and Y from ideal solution having vapour pressures 200 and 100mm Hg respectively. Calculate the mole fraction of component X in vapour phase in equilibrium with an equimolar solution of the two.