What is the conjugate of `(2-i)/((1-2i)^(2))`?

Explanation

To find the conjugate of the complex number \(\frac{2-i}{(1-2i)^2}\), we will follow these steps:

### Step 1: Simplify the denominator
First, we need to simplify \((1-2i)^2\).

\[ (1-2i)^2 = 1^2 - 2 \cdot 1 \cdot 2i + (2i)^2 = 1 - 4i + 4i^2 \]
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