Find the equation of the straight line which passes through the point `(1-2)` and cuts off equal intercepts from axes.
Text Solution
Verified by Experts
The correct Answer is:
N/a
Let the intercepts along the X and Y - axes are a and a respectively. `therefore` Equation of the line is `(x)/(a)+(y)/(a)=1` Since, the point (1-2)lies on the line , `therefore (1)/(a)-(2)/(a)=1` `rArr (1-2)/(a)=1` `rArr a=-1` On putting a =-1in Eq.(i),we get `(x)/(-1)+(y)/(-1)=1` `rArr x+y=-1rArrx+y+1=0`
Topper's Solved these Questions
STRAIGHT LINES
NCERT EXEMPLAR|Exercise Long Answer type|9 Videos
STRAIGHT LINES
NCERT EXEMPLAR|Exercise Objective type questions|20 Videos
STATISTICS
NCERT EXEMPLAR|Exercise FILLERS|7 Videos
TRIGONOMETRIC FUNCTIONS
NCERT EXEMPLAR|Exercise TRUE/FALSE|9 Videos
Similar Questions
Explore conceptually related problems
Find the equation of the straight line whichpasses through the point (2, 3) and cuts off equal intercepts on the axes. (A)
Find the equation of the straight line which passes though (1,-2) and cuts off equal intercepts on the axes.
Find the equation of the straight line which passes through the point (-3,8) and cuts off positive intercepts on the coordinate axes whose sum is 7 .
Find the equation of the straight lines each of which passes through the point (3,2) and cuts off intercepts a and b respectively on x and y- axes such that a-b=2
Find the equation of the line which passes through the point (3, -5) and cuts off intercepts on the axes which are equal in magnitude but opposite in sign.
Find the equation of a line which passes through the point (3,2) and cuts off positive intercepts on X and Y axes in the ratio of 4:3.
Find the equation of the line, which passes through (2, –5) and cuts off equal intercepts on both the axes.
