For what values of `a` and `b`
the intercepts cut off n the coordinate axes by the line `a x+b y+8=0`
are equal in length but opposite in signs to those cut off by the line `2x-3y+6=0`
on the axes.
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Given equation of line `ax+by+8=0` `rArr (x)/((-8)/a)+(y)/((-8)/(b))=1` So, the intercepts are `(-8)/(a)` and `(-8)/(b)`. and another given equation of line is `2x-3y+6=0`. `rArr(x)/(-3)+(y)/(2)=1`. So, the intercepts are `-3` and `2`. According to the question, `(-8)/(a)=3`and `(-8)/(b)=-2` `rArr a=-(8)/(3)`,`b=4`.
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