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If the intercept of a line between the coordinate axes is divided by the point `(-5,4)` in the ratio `1:2,` then find the equation of the line.

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Let intercept of a line are (h,k).
The coordinates of A and B are (h,0)and (0.k)respectively.
`-5=(1xx0+2xxh)/(1+2)`
`rArr -5=(2h)/(3)rArr+h=-(15)/(2)`
and `4=(1.k+0.2)/(1+2)`
`rArr K=12`
`therefore A=(-(15)/(2),0)` and B=(0,12)
Hence the equation of a line AB is
`y-0=(12-0)/(0+15//2)(x+(15)/(2))`
`rArr y=(12.2)/(15)((x+15)/(2))`
`rArr 5y=8x+60rArr8x-5y+60=0`
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