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[" 105A particle executing S.H.M.accordi...

[" 105A particle executing S.H.M.accordign "],[" to equation "4d^(2)x/dt^(2)+320x=0." Its "],[" time period of oscillationis "]

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A particle executes simple harmonic motion according to equation 4(d^(2)x)/(dt^(2))+320x=0 . Its time period of oscillation is :-

A particle executes simple harmonic motion according to equation 4(d^(2)x)/(dt^(2))+320x=0 . Its time period of oscillation is :-

A particle executes simple harmonic motion according to equation 4(d^(2)x)/(dt^(2))+320x=0 . Its time period of oscillation is :-

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For a particle performing SHM , equation of motion is given as (d^(2))/(dt^(2)) + 4x = 0 . Find the time period