=-x^(6)+5x^(3)+8

From the sum of 6x^(4) - 3x^(3) + 7x^(2) - 5x + 1 and -3x^(4) + 5x^(3) - 9x^(2) + 7x - 2 subtract 2x^(4) - 5x^(3) + 2x^(2) - 6x - 8

f:R rarr R o* f(x)=x^(6)-3x^(5)+8x^(3)+5 Then f(x) is

Differentiate each function by applying the basic rules of differentiation 11x^(5)-6x^(3)+8

Differentiate each function by applying the basic rules of differentiation 11x^(5)-6x^(3)+8

Let f(x)=x^(8)-6x^(7)+5x^(6)+x^(4)-5x^(3)-x^(2)-3x+3AA x in R then f(5) is equal to :-

Simplify: 4x^(3)-2x^(2)+5x-1+8x+x^(2)-6x^(3)+7-6x+3-3x^(2)-x^(3)

What should be added to 2x^(3) +6x^(2) -5x +8 to get 3x^(3) -2x^(2) +6x +15?

The transformed equation of x^(3) - 6x^(2) + 5x + 8 = 0 , by eliminating second term is

If x-(1)/(x)=5,xne0 then what is the value of (x^(6)+3x^(3)-1)/(x^(6)-8x^(3)-1) ?