The composition of function is commutative.

Answer

N/a

Explanation

False
Let ` " " f(x) = x^(2)`
and ` " "g(x) =x +1)`
`fog(x)=f{g(x)} =f(x+1)`
` " "=(x+1)^(2)=x^(2)+2x+1`
`gof(x)=g{f(x)}=g(x^(2))=x^(2) +1`
` :. fog(x) ne gof(x)`