The composition of functtions is associative

Answer

N/a

Explanation

True
Let ` " " f(x)=x, g(x)=x+1`
and ` " " h(x)=2x-1`
Then, ` " " fo{goh(x)}=f[g{h(x)}]`
` =f{g(2x-1)}`
`=f(2x-1+1)`
`=f(2x)=2x`
` :. (fog)oh(x)=(fog){h(x)}`
`=(fog)(2x-1)`
`=f{g(2x-1)}`
`=f(2x-1+1)`
`=f(2x)=2x`