int((1+cosx))/(x+sinx)dx...

`int((1+cosx))/(x+sinx)dx`

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The correct Answer is:

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Consider that, `I = int((1+cosx))/((x+sinx))dx`
Let `x + sinx = t rArr (1+cosx)dx = dt`
`:. I = int(1)/(t) dt = log|t|+C`
` = log|(x+sinx)|+C`

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