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int (dx)/(sqrt(16-9x^(2)))...

`int (dx)/(sqrt(16-9x^(2)))`

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The correct Answer is:
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Let `I = int(dx)/(sqrt(16-9x^(2))) = int(dx)/(sqrt((4)^(2) - (3x)^(2))) = 1/3 sin^(-1)((3x)/4)+C`
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