Maximise Z=x+y subject to `x+4y le 8 , 2x+3y le 12, 3x+y le 9, x ge 0, and y ge 0`

Answer

N/a

Explanation

Here the given LPP is

Maximise Z=X+Y subject to
`x+4y ge 8, 2x+3y le 12, 3x+y le 9, x ge 0,y ge 0`
On solving x+4y=8 and 3x+y=9 we get
`x=(28)/(11),y=(15)/(11)`
From the feasible region, it is clear that coordinates of corner points are (0,0), (3,0) `(28)/(11),(15)/(11)` and (0,2)

Hence, the maximum value is `3(10)/(11)`