" (ii) "y=sin(x+y)

Prove that: (i) ("sin"(x-y))/("sin"(x+y))=("tan"x-"tan"y)/("tan"x+"tan"y)

If (x +y) = sin (x + y) " then " (dy)?(dx)= ?

Find dy/dx if y = sin( x+y )

Find (dy)/(dx) , if x+y=sin(x-y)

Solve sin x+sin y=sin(x+y) and |x|+|y|=1

Solutions of the differential equations (dy)/(dx) tan y= sin (x+y) +sin (x-y) is

Prove that (i) 2 cos x cos y=cos (x+y)+cos (x-y) (ii) -2 . sin x sin y=cos (x+y)-cos (x-y) (iii) 2 sin x cos y=sin (x+y)+sin (x-y) (iv) 2 cos x sin y=sin (x+y)-sin (x-y)

The solution of differential equation [x cos ((y) / (x)) + y sin ((y) / (x))] y- [y sin ((y) / (x)) - x cos ((y ) / (x))] x (dy) / (dx) = 0