Two batteries of emf `epsi_(1) and epsi_(2)(epsi_(2) gt epsi_(1))` and internal resistance `r_(1) and r_(2)` respectively are connected in parallel as shown in figure.

Options

A. The equivalent emf `epsi_(eq)` of the two cells is between `epsi_(1) and epsi_(2)`, i.e., `epsi_(1) lt epsi_(eq) lt epsi_(2)`
B. the equivalent emf `epsi_(eq)` is smaller than `epsi_(1)`
C. The `epsi_(eq)` is given by `epsi_(eq)=epsi_(1)+epsi_(2)` always.
D. `epsi_(eq)` is independent of internal resistance `r_(1) and r_(2)`.

Answer

A

Explanation

The equivalent emf of this combination is given by
`epsi_(eq)=(epsi_(2)r_(1)+epsi_(1)r_(2))/(r_(1)+r_(2))`
This suggest that the equivalent emf `epsi_(eq)` of the two cells is given by
`epsi_(1) lt epsi_(eq) lt epsi_(2)`.