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Two charged particles traverse identical...

Two charged particles traverse identical helical paths in a completely opposite sense in a uniform magnetic field `vec(B)=B_(0)hat(K)`

A

They have equal z-components of momenta

B

They must have equal charges.

C

They necessarily represent a particle, anti partile pair

D

The charge to mass ratio satisfty.

Text Solution

Verified by Experts

The correct Answer is:
D
For given pitch d correspond to charge particle, we have
`(q)/(m)=(2pivcostheta)/(qB)="constant"`
Since, charged particles traverse identical helical paths in a completely opposite sense in a uniform magnetic field B, LHS for two particle should be same and of opposite dign, therefore.
`((e)/(m))_(1)+((e)/(m))_(2)=0`
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Knowledge Check

  • Two charged particles traverse identical helical paths in a completely opposite sense in a uniform magnetic field vecB=B_0hatk .

    A
    They have equal z-components of momenta
    B
    They must have equal charges
    C
    They necessarily represent a particle-antiparticle pair
    D
    The charge to mass ratio satisfy:
    `(e/m)_1+(e/m)_2=0`

  • A charged particle moving along +ve x-direction with a velocity v enters a region where there is a uniform magnetic field B_0(-hat k), from x=0 to x=d. The particle gets deflected at an angle theta from its initial path. The specific charge of the particle is

    A
    `(v cos theta)/(Bd)`
    B
    `(v tan theta)/(Bd)`
    C
    `v/(Bd)`
    D
    `(v sin theta)/(Bd)`

  • The path of a charged particle moving in a uniform steady magnetic field cannot be a

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    straight line
    B
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    C
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