A circular current loop of magnetic moment `M` is in an arbitrary orientation in an external magnetic field `vec(B)`. The work done to rotate the loop by `30^(@)` about an axis perpendicular to its plane is `:`

Options

A. `MB`
B. `sqrt(3)(MB)/(2)`
C. `(MB)/(2)`
D. zero

Answer

A

Explanation

The rotation of the loop by `30^(@)` about an axis perpendicular to its plane make no change in the angle made by axis of the loop with the direction of magnetic field therefore,t he work done to rotate the loop is zero.