Consider the diffraction pattern for a small pinhole. As the size of the hole is increased

Options

A. the size decrease
B. the intensity increase
C. the size increase
D. the intensity decrease

Answer

A, B

Explanation

(a,b) (a) When a decrease w increases.
So, size decreases.
(b) Now, light energy is distributed over a small are and intensity `prop(1)/("area")` as area is decreasing so intensity increases.