The wavelength of a photon needed to remove a proton from a nucleus which is bound to the nucleus with 1MeV energy is nearly

Options

A. 1.2 nm
B. `1.2xx10^(-3)` nm
C. `1.2xx10^(-6)`nm
D. `1.2xx10` nm

Explanation

Given in the question,
Energy of photon, `E=1MeVimplies=10^(6)eV`
Now, `" "hc=1240 eVnm`
Now, `" "E=(hc)/(lamda)`
`implies" "l=(hc)/(E)=(1240eVnm)/(10^(6)eV)`
`" "=1.24xx10^(-3)` nm