If Q is a point on the side SR of a triangle PSR such that PQ=PR then prove that `PS > PQ`

Explanation

To prove that \( PS > PQ \) given that \( PQ = PR \) in triangle \( PSR \) where \( Q \) is a point on side \( SR \), we can follow these steps:

### Step 1: Identify the Angles
Let’s label the angles in triangle \( PSR \) and triangle \( PQR \):
- Let \( \angle PQR = \angle 1 \)
- Let \( \angle PRQ = \angle 2 \)
- Let \( \angle QRP = \angle 3 \)
- Let \( \angle PSQ = \angle 4 \)
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