ABC is a right triangle with AB = AC.If bisector of `angle A ` meet BC at D then prove that BC =2 AD .

Explanation

To prove that \( BC = 2AD \) in the right triangle \( ABC \) where \( AB = AC \) and the angle bisector of \( \angle A \) meets \( BC \) at \( D \), we can follow these steps:

### Step 1: Understand the Triangle
Since \( ABC \) is a right triangle with \( AB = AC \), it is an isosceles right triangle. Therefore, \( \angle A = 90^\circ \) and \( \angle B = \angle C = 45^\circ \).

### Step 2: Identify Angles
Since \( D \) is the point where the angle bisector of \( \angle A \) meets \( BC \), it divides \( \angle A \) into two equal angles:
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