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The point which divides the line segment...

The point which divides the line segment joining the points (7,-6) and (3,4) in ratio ` 1 : 2` internally lies in the

A

I quadrant

B

II quadrant

C

III quadrant

D

Iv quadrant

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To find the point that divides the line segment joining the points \( A(7, -6) \) and \( B(3, 4) \) in the ratio \( 1:2 \) internally, we can use the section formula. The section formula states that if a point \( P(x, y) \) divides the line segment joining the points \( A(x_1, y_1) \) and \( B(x_2, y_2) \) in the ratio \( m:n \), then the coordinates of point \( P \) can be calculated using the following formulas: \[ x = \frac{m \cdot x_2 + n \cdot x_1}{m + n} \] \[ y = \frac{m \cdot y_2 + n \cdot y_1}{m + n} \] ### Step 1: Identify the coordinates and the ratio - Let \( A(7, -6) \) be \( (x_1, y_1) \) and \( B(3, 4) \) be \( (x_2, y_2) \). - The ratio \( m:n = 1:2 \) means \( m = 1 \) and \( n = 2 \). ### Step 2: Calculate the x-coordinate of the dividing point Using the formula for \( x \): \[ x = \frac{1 \cdot 3 + 2 \cdot 7}{1 + 2} \] \[ x = \frac{3 + 14}{3} = \frac{17}{3} \] ### Step 3: Calculate the y-coordinate of the dividing point Using the formula for \( y \): \[ y = \frac{1 \cdot 4 + 2 \cdot (-6)}{1 + 2} \] \[ y = \frac{4 - 12}{3} = \frac{-8}{3} \] ### Step 4: Combine the coordinates to find the point The point \( P \) that divides the line segment in the ratio \( 1:2 \) is: \[ P\left(\frac{17}{3}, \frac{-8}{3}\right) \] ### Step 5: Determine the quadrant of the point - The x-coordinate \( \frac{17}{3} \) is positive. - The y-coordinate \( \frac{-8}{3} \) is negative. Since the x-coordinate is positive and the y-coordinate is negative, the point lies in the **fourth quadrant**. ### Final Answer The point which divides the line segment joining the points \( (7, -6) \) and \( (3, 4) \) in the ratio \( 1:2 \) internally is \( \left(\frac{17}{3}, \frac{-8}{3}\right) \) and it lies in the **fourth quadrant**.

To find the point that divides the line segment joining the points \( A(7, -6) \) and \( B(3, 4) \) in the ratio \( 1:2 \) internally, we can use the section formula. The section formula states that if a point \( P(x, y) \) divides the line segment joining the points \( A(x_1, y_1) \) and \( B(x_2, y_2) \) in the ratio \( m:n \), then the coordinates of point \( P \) can be calculated using the following formulas: \[ x = \frac{m \cdot x_2 + n \cdot x_1}{m + n} \] \[ y = \frac{m \cdot y_2 + n \cdot y_1}{m + n} \] ...
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NCERT EXEMPLAR-COORDINATE GEOMETRY-Coordinate Geometry
  1. The area of a triangle with vertices A(3,0),B(7,0) and C(8,4) is

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  2. The points (-4,0),(4,0) and (0,3) are the verticess of a

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  3. The point which divides the line segment joining the points (7,-6) and...

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  4. The point which lies on the perpendicular bisector of the line segment...

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  5. The fourth vertex D of a parallelogram ABCD whose three vertices are ...

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  6. if A(2,1) cuts line P(2,1) and B(8,4) then

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  7. If P((a)/(3),4) is the mid - point of the line segment joining the poi...

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  8. The perpendicular bisector of the line segment joining the points A(1,...

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  9. The coordinates of the point which is equidistant from the three verti...

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  10. If a circle drawn with origin as the centre passes through (13/(2),0)...

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  11. A line intersects the Y- axis and X-axis at the points P and Q, respec...

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  12. The area of a triangle with vertices (a,b+c), (b,c+a) and (c,a+b) is

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  13. If the distance between the points (4,p) and (1,0) is 5 , then find t...

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  14. If the points A(1,2) , B(0,0) and C (a,b) are collinear , then

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  15. triangle ABC with vertices A(0-2,0),B(2,0) and C(0,2) is similar to tr...

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  16. The point P(-4,2) lies on the line segment joining the points A(-4,6) ...

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  17. The points (0,5) , (0,-9) and (3,6) are collinear.

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  18. Point P(0,2) is the point of intersection of Y-axis and perpendicular ...

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  19. The points A(3,1) , B (12,-2) and C(0,2) cannot be vertices of a trian...

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  20. Prove that the points A(4,3), B(6,4), C(5,-6) and D(-3,5) are vertices...

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