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The points A(3,1) , B (12,-2) and C(0,2)...

The points A(3,1) , B (12,-2) and C(0,2) cannot be vertices of a triangle.

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To determine whether the points A(3, 1), B(12, -2), and C(0, 2) can be vertices of a triangle, we can calculate the area of the triangle formed by these points. If the area is zero, it indicates that the points are collinear and do not form a triangle. ### Step-by-Step Solution: 1. **Identify the Coordinates:** - Let A = (x1, y1) = (3, 1) - Let B = (x2, y2) = (12, -2) - Let C = (x3, y3) = (0, 2) 2. **Use the Area Formula:** The area \( A \) of a triangle formed by three points \((x_1, y_1)\), \((x_2, y_2)\), and \((x_3, y_3)\) can be calculated using the formula: \[ A = \frac{1}{2} \left| x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2) \right| \] 3. **Substitute the Coordinates into the Formula:** Substitute the values of A, B, and C into the area formula: \[ A = \frac{1}{2} \left| 3((-2) - 2) + 12(2 - 1) + 0(1 - (-2)) \right| \] 4. **Calculate Each Term:** - Calculate \( 3((-2) - 2) = 3 \times (-4) = -12 \) - Calculate \( 12(2 - 1) = 12 \times 1 = 12 \) - The term with \( 0 \) will be \( 0(1 - (-2)) = 0 \) 5. **Combine the Results:** Combine the results from the calculations: \[ A = \frac{1}{2} \left| -12 + 12 + 0 \right| = \frac{1}{2} \left| 0 \right| = 0 \] 6. **Conclusion:** Since the area \( A = 0 \), it indicates that the points A, B, and C are collinear and do not form a triangle. ### Final Statement: The points A(3, 1), B(12, -2), and C(0, 2) cannot be vertices of a triangle because they are collinear. ---

To determine whether the points A(3, 1), B(12, -2), and C(0, 2) can be vertices of a triangle, we can calculate the area of the triangle formed by these points. If the area is zero, it indicates that the points are collinear and do not form a triangle. ### Step-by-Step Solution: 1. **Identify the Coordinates:** - Let A = (x1, y1) = (3, 1) - Let B = (x2, y2) = (12, -2) - Let C = (x3, y3) = (0, 2) ...
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NCERT EXEMPLAR-COORDINATE GEOMETRY-Coordinate Geometry
  1. The points (0,5) , (0,-9) and (3,6) are collinear.

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  2. Point P(0,2) is the point of intersection of Y-axis and perpendicular ...

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  3. The points A(3,1) , B (12,-2) and C(0,2) cannot be vertices of a trian...

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  4. Prove that the points A(4,3), B(6,4), C(5,-6) and D(-3,5) are vertices...

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  5. A circle has its centre at the origin and a point P (5,0) lies on it ....

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  6. The point A (2,7) lies on the perpendicular bisector of the line segm...

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  7. The point P (5,-3) is one of the two points of trisection of line segm...

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  8. The points A (-6,10), B(-4,6) and C(3,-8) are collinear such that ...

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  9. The points P (-2,4) lies on a circle of radius 6 and centre (3,5).

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  10. The points A (-1,-2), B (4,3) ,C (2,5) and D (-3,0) in that order form...

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  11. Name the type of triangle formed by the points A (-5,6) , B (-4,-2) an...

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  12. Find the points on the X-axis which are at distance of 2sqrt(5) from...

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  13. What type of quadrilateral do the points A (2,-2), B (7,3), C(11,-1) a...

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  14. Find the value of a , if the distance between the points A (-3,-14) an...

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  15. Find a point which is equidistant from the points A(-5,4) and B (-1,6)...

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  16. Find the coordinates of the point Q on the X- axis which lies on the ...

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  17. Find the value of m, if the points (5,1), (-2,-3) and (8,2m) are colli...

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  18. If the points A(2,-4) is equidistant from P (3,8) and Q (-10,y), then ...

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  19. Find the area of the triangle wohose vertices are (-8,4) ,(-6,6) and (...

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  20. In what ratio does the X -axis divide the line segment joining the poi...

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