Find the area of the triangle wohose vertices are (-8,4) ,(-6,6) and (-3,9).

Explanation

Given that , the vertices of triangles
Let `(x_(1),y_(1))to(-8,4)`
`(x_(2),y_(2))to(-6,6)`
and `(x_(3),y_(3))to(-3,9)`
we know that , the area of triangle with vertices `(x_(1),y_(1)),(x_(2),y_(2))and (x_(3),y_(3))`
`triangle=(1)/(2)[x_(1)(y_(2)-y_(3))+x_(2)(y_(3)-y_(1))+x_(3)+(y_(1)-y_(2))]`
`:.=(1)/(2)[-8(6-9)-6(9-4)+(-3)(4-6)]`
`=(1)/(2)[-8(-3)-6(5)-3(-2)]=(1)/(2)(24-30+6)`
`=(1)/(2)(30-30)=(1)/(2)(0)=0`
Hence , the required area of triangle is 0.