Home
Class 10
MATHS
The following is the frequency distribut...

The following is the frequency distribution of duration for 100 calls made on the mobile phone

Calculate the average duration (in sec) of a call and also find the median from a cumulative frequency curve.

Text Solution

Verified by Experts

First, we calculate class marks as follows

Here, (assumed mean)a=170
and (class width)h=30
By step deviation method.
`"Average"(bar(x))=a+(sumf_(i)u_(i))/(sumf_(i))xxh=170+(1)/(100)xx30`
=170+0.3=170.3
Hence, average duration is 170.3s.
For calculating median from a cumulative frequency curve
We prepare less than type or more than type ogive We observe that, the number of calls in less then 95 s as well as the number of calls from 95-125 .s So, the total number of calls in less than 125 s is 0+14=14. Continuing in this manner, we will get remaining in less than 155,185,215 and 245s.
Now, we construct a table for lesst han type ogive (cumulative frequency curve)

To draw less than ogive we plot them the points (95,0),(125,14),(155,36),(185,64),(214,85),(245,100) on the paper and join them by free hand.

`therefore` Total number of calls (n)=100
`(n)/(2)=(100)/(2)=50`
Now, point 50 taking on Y-axis drw a line parallel to X-axis meet at a point P and draw a perpendicular line from P to the X-axis, the intersection point X-axis is the meidan, Hence, required median is 170.
Promotional Banner

Topper's Solved these Questions

  • STATISTICS AND PROBABILITY

    NCERT EXEMPLAR|Exercise VERY SHORT ANSWERS QUESTIONS|2 Videos
  • REAL NUMBERS

    NCERT EXEMPLAR|Exercise Real Numbers|39 Videos
  • SURFACE AREAS AND VOLUMES

    NCERT EXEMPLAR|Exercise Surface Areas And Volumes|62 Videos

Similar Questions

Explore conceptually related problems

The median of following frequency distribution is 24 years. Find the missing frequency x.

Find the median for the following frequency distribution

Find the median for the following frequency distribution

Find the mean from the following frequency distribution: