The polar form of `sin theta-i cos theta` is

write the polar form of 1-cos theta+i sin theta

The mod-amp form of 1+cos theta+i sin theta is

The mod-amp form of 1+cos theta+i sin theta is

We express ((cos 2theta -i sin 2theta)^(4) (cos 4theta + i sin 4 theta)^(-5))/((cos 3theta + i sin 3theta)^(-2) (cos 3theta -i sin 3theta)^(-9)) in the form of x+iy , we get

The polar equation cos theta + 7 sin theta= (1)/(r ) represents a

(sin theta + cos theta)/(sin theta - cos theta) + (sin theta - cos theta)/(sin theta + cos theta)= ________

(cos theta + i sin theta) (cos3 theta + i sin3 theta) .......... (cos (2r-1) theta + i sin (2r-1) theta) = 1

if a=cos theta + i sin theta , b=cos 2 theta- i sin 2 theta , c= cos 3theta + i sin 3theta and if |{:(a,,b,,c),(b,,c,,a),(c,,a,,b):}| =0 then