Cosider Lines `L_1:(x-alpha)/1=y/-2=(z+beta)/2.L_2:x=alpha,y/-alpha=(z+alpha)/(2-beta),` Plane `p:2x+2y+z+7=0.` Let line `L_2` line in plane p, then

Line (x-2)/alpha=(y-2)/(-3)=(z+2)/2 lies in x+3y-2z+beta=0 then alpha+beta= ?

Two lines L_(1) : x=5, (y)/(3-alpha)=(z)/(-2) and L_(2) : x=alpha, (y)/(-1)=(z)/(2-alpha) are coplanar. Then, alpha can take value(s)

Two lines L_(1) : x=5, (y)/(3-alpha)=(z)/(-2) and L_(2) : x=alpha, (y)/(-1)=(z)/(2-alpha) are coplanar. Then, alpha can take value(s)

Two lines L_(1) : x=5, (y)/(3-alpha)=(z)/(-2) and L_(2) : x=alpha, (y)/(-1)=(z)/(2-alpha) are coplanar. Then, alpha can take value(s)

Two lines L_(1) : x=5, (y)/(3-alpha)=(z)/(-2) and L_(2) : x=alpha, (y)/(-1)=(z)/(2-alpha) are coplanar. Then, alpha can take value(s)

Two lines L_(1):x=5,(y)/(3-alpha)=(z)/(-2) and L_(2):x=alpha,(y)/(-1)=(z)/(2-alpha) are coplanar.Then alpha can take value (s) a.1 b.2 c.3 d.4

If for some alpha in R, the lines L_1 : (x + 1)/(2) = (y-2)/(-1) = ( z -1)/(1) and L_2 : (x + 2)/(alpha) = (y +1)/(5 - alpha) = (z + 1)/(1) are coplanar , then the line L_2 passes through the point :

Two lines L_(1): x = 5, (y)/(3-alpha) = (z)/(-2) and L_(2) : x = alpha, (y)/(-1) = (z)/(2- alpha) are coplanar. Then alpha can take value (s)

Two lines L_1: x=5, y/(3-alpha)=z/(-2) and L_2: x=alpha, y/(-1)=z/(2-alpha) are coplanar. Then alpha can take value (s) a. 1 b. 2 c. 3 d. 4