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" 2."(4)/(x)-3=(5)/(2x+3),quad x!=0,(-3)...

" 2."(4)/(x)-3=(5)/(2x+3),quad x!=0,(-3)/(2)

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Solve for: (4)/(x)-3=(5)/(2x+3),x!=0,quad -(3)/(2)

Solve for: 4/x-3=5/(2x+3),x!=0,,-3/2

Take away: (6)/(5)x^(2)-(4)/(5)x^(3)+(5)/(6)+(3)/(2)x om (x^(3))/(3)-(5)/(2)x^(2)+(3)/(5)x+(1)/(4)

3(x+4)-2(x-2)=5(x+5)+3

Solve x(x+2)^(2)(x-1)^(5)(2x-3)(x-3)^(4)>=0

Observe the following pattern (1x2)+(2x3)=(2x3x4)/(3)(1x2)+(2x3)+(3x4)=(3x4x5)/(3)(1x2)+(2x3)+(3x4)+(4x5)=(4x5x6)/(3) and find the of (1x2)+(2x3)+(3x4)+(4x5)+(5x6)

5(x-4)-2(3-2x)=4(x+2)-3(2-3x)

((x-5)^(2)(x+2)^(3)(x-4))/((x-3)^(4))<=0

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x^2-2x+2=0"( 2)"x^2-3x+3=0x^2-3x+4=0"( 4)"x^2-5x+5=0 A quadratic equation whose roots are cosec20 andsec 0 can be(1) x2-2x+ 2 =0(2) x2-3x + 3 = 0(3) x2-3x+ 4= 0(4) x-5x+5= 0