" Q3.2"x=Sec A&2/x=tan A" then "2(x^(2)-1/x^(2))=?

If sec A+tan A=x then sec A=(x^(2)-1)/(x)

If 2x = sec theta and 2/x = tan theta , then 2(x^2 - (1)/(x^2)) =

If 3x=sec theta,(3)/(x) =tan theta then (x^(2)-(1)/(x^(2))) I equal to:

If 2x= sec A " and "2/x = tan A , then the value of 2(x^2 - 1/x^2) will be

sec 2x - tan 2x=

if sec A=2x and tan A=(2)/(x), find the value of 2(x^(2)-(1)/(x^(2)))

If tan(x/2)=cosec x-sin x" then (1+sec^(2)(x)/(2))^(2)=

If tan theta+sec theta=x" show that 2 tan "theta=x -1/x, 2 sec theta=x+1/x. Hence show that sin theta=(x^(2)-1)/(x^(2)+1)

tan theta+sec theta=x show that 2tan theta=x-(1)/(x),2sec theta=x+(1)/(x) hence prove that sin theta=(x^(2)-1)/(x^(2)+1)