If the area of an isosceles triangle is `sqrt2+1` and vertical angle is `45^@` then the base of the triangle is

If the area os an isosceles triangle is sqrt2 + 1 and vertical angle is 45^(@) then the base of the triangle is

If the area of an isosceles triangle is sqrt(2)+1 and vertical angle is 45^(@) then the base of the triangle is

If the area of an isosceles triangle is sqrt2+1 are vertical angle is 45^@ then the base of the triangle is

One of the base angles of an isosceles triangle is 70^(@) . The vertical angle is

Find the area of the isosceles triangle with base 16 cm and vertical angle 60^(@)40'

Each base angle of an isosceles triangle is 15^(@) more than its vertical angle. Find each angle of the triangle.

The lateral sides of an isosceles triangle with vertex angle 90^(@) are 12cm each.Find the area of the triangle and hence its base

The lateral sides of an isosceles triangle with vertex angle 60^(@) are 12cm each.Find the area of the triangle and hence its base.

If the orthocenter of an isosceles triangle lies on the incircle of the triangle then A) the base angle of the triangle is cos^-1 2/3 B) the triangle is acute C) the base angle of the triangle is tan^-1 (sqrt5/2) D) If S, I are the circumcentre and incentre and R is circumradius then SI/R=1/3