" I2/ Three sides "AB,BC" and "CA" of a triangle "ABC" are "5x-3y+2=0,x-3y-2=

Three sides AB,AC and CA of triangle ABC are 5x-3y+2=0,x-3y-2=0 and x+y-6=0 respectively.Find the equation of the altitude through the vertex A.

Three sides A B ,A Ca n dC A of triangle A B C are 5x-3y+2=0,x-3y-2=0a n dx+y-6=0 respectively. Find the equation of the altitude through the vertex Adot

The three sides AB, BC, CA of a triangle are 5x - 3y +2 = 0,x-3y-2=0 and x+y-6=0 respectively. Find equation of the altitude through the vertex A.

The equations of the sides AB, BC and CA of a triangle ABC are x-2=0, y+1=0 and x + 2y - 4=0 respectively. What is the equation of the altitude through B on AC?

The equations of the sides AB,BC,CA of a triangle ABC are 2x-y-3=0,6x+y-21=0 and 2x+y-5=0 respectively.The external bisector of angle A passes through the point

The equations of the perpendicular bisectors of the sides AB and AC of a triangle ABC are x -y+5=0 and x+2y=0 respectively . If the point A is (1,-2) , find the equation of the line BC.

The equation of perpendiculars of the sides AB and AC of triangle ABC are x-y-4=0 and 2x-y-5=0 respectively.If the vertex A is (-2,3) and point of intersection of perpendicular bisectors is ((3)/(2),(5)/(2)) find the equation of medians to the sides AB& AC respectively