[3n+4y=1],[4x+3y+2k=0],[1,1)" equidis tayt "]

For what value of k are the two straight lines 3x+4y=1 and 4x+3y+2k=0 equidistant from the point (1, 1) ?

x-3y=1,3x-2y+4=0

The lines 4x+4y =1,8x -3y =2 and y=0 are-

The tangents to the circle x^(2)+y^(2)-4x+2y+k=0 at (1,1) is x-2y+1=0 then k=

The tangent to the circle x^(2)+y^(2)-4x+2y+k=0 at (1,1) is x-2y+1=0 then k=

The tangent to the circle x^(2)+y^(2)-4x+2y+k=0 at (1,1) is x-2y+1=0 then k=

If the lines x - y - 1 = 0, 4x + 3y = k and 2x – 3y +1 = 0 are concurrent, then k is

Find for what value of k the three straight lines 4x-3y=1 , 3x-4y+1=0 and kx-7y +3=0 are concurrent .