" (i) "x^(2)+y^(2)+10x-2y+22=0,quad x^(2)+y^(2)+2x-8y+8=0

The circles whose equations are x^(2)+y^(2)+10x-2y+22=0 and x^(2)+y^(2)+2x-8y+8=0 touch each other. The circle which touch both circles at, the point of contact and passing through (0,0) is, 1) 9(x^(2)+y^(2))-15x-20y=0, 2) 5(x^(2)+y^(2))-18x-80y=0 3) 7(x^(2)+y^(2))-18x-80y=0, 4) x^(2)+y^(2)-9x-40y=0 ]]

Find the equation of the common tangent of the following circles at their point of contact x^(2)+y^(2)=10x-2y+22=0, x^(2)+y^(2)+2x=8y+8=0

Two circles x^(2) + y^(2) - 2x - 4y = 0 and x^(2) + y^(2) - 8y - 4 = 0

Prove that the centres of the circle x^(2) + y^(2) - 4x - 2y + 4 = 0, x^(2) + y^(2) - 2x - 4y + 1 = 0 and x^(2) + y^(2) + 2x - 8y + 1 = 0 are collinear. More over prove that their radii are in geometric pregression.

find the equation of the common tangent of the following circles at their point of contact. x^2 + y^2 + 10x - 2y + 22 = 0 , x^2 + y^2 + 2x - 8y + 8 =0 .

If the circles x^(2)+y^(2)+10x+8y+c=0 and x^(2)+y^(2)-10x-8y+c=0 cut onbogonally,then the value of 'C'' is

The angle at which the circles x^(2) + y^(2) + 8x - 2y - 9 = 0 , x^(2) + y^(2) - 2x + 8y - 7 = 0 in tersect is