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The least number divisible by each of th...

The least number divisible by each of the numbers 15, 20, 24, 32 and 36 is

A

1660

B

2880

C

1440

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To find the least number divisible by each of the numbers 15, 20, 24, 32, and 36, we will calculate the Least Common Multiple (LCM) of these numbers. Here’s a step-by-step solution: ### Step 1: Prime Factorization First, we will find the prime factorization of each number. - **15**: \(3 \times 5\) - **20**: \(2^2 \times 5\) - **24**: \(2^3 \times 3\) - **32**: \(2^5\) - **36**: \(2^2 \times 3^2\) ### Step 2: Identify the Highest Powers of Each Prime Next, we will identify the highest power of each prime factor from the factorizations: - For **2**: The highest power is \(2^5\) (from 32). - For **3**: The highest power is \(3^2\) (from 36). - For **5**: The highest power is \(5^1\) (from 15 and 20). ### Step 3: Calculate the LCM Now, we will multiply these highest powers together to find the LCM: \[ \text{LCM} = 2^5 \times 3^2 \times 5^1 \] Calculating this step-by-step: 1. Calculate \(2^5 = 32\) 2. Calculate \(3^2 = 9\) 3. Calculate \(5^1 = 5\) Now multiply these results together: \[ 32 \times 9 = 288 \] \[ 288 \times 5 = 1440 \] ### Final Answer The least number divisible by each of the numbers 15, 20, 24, 32, and 36 is **1440**. ---
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