What least number must be added to `1056` to get a number exactly divisible by `23`?

Options

A. `21`
B. `8`
C. `2`
D. `9`

Answer

To find the least number that must be added to `1056` to make it exactly divisible by `23`, we can follow these steps:

### Step-by-Step Solution:

1. **Divide 1056 by 23**:
We need to find how many times `23` fits into `1056`.
\[ 1056 \div 23 = 45 \quad \text{(approximately)} \]
To find the exact quotient, we can multiply:
\[ 23 \times 45 = 1035 \]

2. **Calculate the Remainder**:
Now, we subtract `1035` from `1056` to find the remainder.
\[ 1056 - 1035 = 21 \]
So, the remainder when `1056` is divided by `23` is `21`.

3. **Determine the Amount to Add**:
To make `1056` exactly divisible by `23`, we need to add a number that will eliminate the remainder. Since the remainder is `21`, we can find out how much more we need to reach the next multiple of `23`.
\[ 23 - 21 = 2 \]

4. **Final Calculation**:
Therefore, the least number that must be added to `1056` to make it divisible by `23` is `2`.

### Conclusion:
The answer is **2**.