Arrange the following fraction in descending order:
`(1)/(12), (1)/(23), (1)/(7), (1)/(9), (1)/(17), (1)/(50)`

Answer

To arrange the fractions \( \frac{1}{12}, \frac{1}{23}, \frac{1}{7}, \frac{1}{9}, \frac{1}{17}, \frac{1}{50} \) in descending order, we will follow these steps:

### Step-by-Step Solution:

1. **Identify the fractions**: We have the following fractions to arrange:
\[ \frac{1}{12}, \frac{1}{23}, \frac{1}{7}, \frac{1}{9}, \frac{1}{17}, \frac{1}{50} \]

2. **Understand the concept of descending order**: In descending order, we arrange numbers from the largest to the smallest. Since all the fractions have the same numerator (1), we will compare their denominators.

3. **Compare the denominators**: The smaller the denominator, the larger the fraction. Therefore, we need to identify the smallest to largest denominators:
- Denominators: 12, 23, 7, 9, 17, 50
- Arranging these from smallest to largest gives us: 7, 9, 12, 17, 23, 50.

4. **List the fractions in order of their denominators**:
- The largest fraction corresponds to the smallest denominator:
- \( \frac{1}{7} \) (smallest denominator)
- \( \frac{1}{9} \)
- \( \frac{1}{12} \)
- \( \frac{1}{17} \)
- \( \frac{1}{23} \)
- \( \frac{1}{50} \) (largest denominator)

5. **Write the fractions in descending order**:
\[ \frac{1}{7}, \frac{1}{9}, \frac{1}{12}, \frac{1}{17}, \frac{1}{23}, \frac{1}{50} \]

### Final Answer:
The fractions arranged in descending order are:
\[ \frac{1}{7}, \frac{1}{9}, \frac{1}{12}, \frac{1}{17}, \frac{1}{23}, \frac{1}{50} \]