Reena is 6 years older than her brother Ajay. If the sum of their ages is 28 years, what are their present ages ?

Answer

To find the present ages of Reena and Ajay, we can follow these steps:

### Step 1: Define the variables
Let Ajay's present age be represented by \( X \).

### Step 2: Express Reena's age in terms of Ajay's age
Since Reena is 6 years older than Ajay, we can express Reena's age as:
\[ \text{Reena's age} = X + 6 \]

### Step 3: Set up the equation based on the given information
According to the problem, the sum of their ages is 28 years. Therefore, we can write the equation:
\[ X + (X + 6) = 28 \]

### Step 4: Simplify the equation
Combine like terms in the equation:
\[ 2X + 6 = 28 \]

### Step 5: Solve for \( X \)
To isolate \( X \), subtract 6 from both sides:
\[ 2X = 28 - 6 \]
\[ 2X = 22 \]

Now, divide both sides by 2:
\[ X = \frac{22}{2} \]
\[ X = 11 \]

### Step 6: Find Reena's age
Now that we have Ajay's age, we can find Reena's age:
\[ \text{Reena's age} = X + 6 = 11 + 6 = 17 \]

### Conclusion
Ajay's present age is 11 years, and Reena's present age is 17 years.

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