Fill in the blanks
i `(-6)xx(........) = 6`
ii `(-18)xx(.......) = (-18)`
iii `(-8) xx (-9) = (-9) xx (...)`
iv `7 xx (-3) = (-3) xx (…)`
v `{(-5)x3}x(-6) = (...)xx{3xx(-6)}`
vi `(-5)x(...)=0`

Answer

Let's solve the questions step by step:

### i. `(-6) x (........) = 6`
To find the missing number, we need to determine what number multiplied by -6 gives us 6.

- We know that multiplying two negative numbers results in a positive number.
- Therefore, we can conclude that:
\[ (-6) \times (-1) = 6 \]
So, the blank can be filled with **-1**.

### ii. `(-18) x (.......) = (-18)`
Here, we need to find a number that when multiplied by -18 gives -18.

- We know that any number multiplied by 1 remains the same.
- Therefore:
\[ (-18) \times 1 = -18 \]
So, the blank can be filled with **1**.

### iii. `(-8) x (-9) = (-9) x (...)`
This equation is based on the commutative property of multiplication, which states that changing the order of factors does not change the product.

- Here, we can see that:
\[ (-8) \times (-9) = (-9) \times (-8) \]
So, the blank can be filled with **-8**.

### iv. `7 x (-3) = (-3) x (…)`
Again, this is an application of the commutative property.

- We can write:
\[ 7 \times (-3) = (-3) \times 7 \]
So, the blank can be filled with **7**.

### v. `{(-5) x 3} x (-6) = (...) x {3 x (-6)}`
This question uses the associative property of multiplication, which states that the way in which numbers are grouped does not change the product.

- We can rewrite it as:
\[ (-5) \times 3 = (-5) \]
So, the blank can be filled with **-5**.

### vi. `(-5) x (...) = 0`
To find the missing number, we need to determine what number multiplied by -5 gives us 0.

- We know that any number multiplied by 0 results in 0.
- Therefore:
\[ (-5) \times 0 = 0 \]
So, the blank can be filled with **0**.

### Summary of Answers:
i. -1
ii. 1
iii. -8
iv. 7
v. -5
vi. 0

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